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标题: 点阵式LED简单图形显示技术 [打印本页]

作者: qitianwen 时间: 2008-4-4 19:20 标题: 点阵式LED简单图形显示技术

点阵式LED简单图形显示技术1．实验任务
在8X8点阵式LED显示“★”、“●”和心形图，通过按键来选择要显示的图形。
2．电路原理图

　　图4.26.1
3．硬件系统连线
(1)．把“单片机系统”区域中的P1端口用8芯排芯连接到“点阵模块”区域中的“DR1－DR8”端口上；
(2)．把“单片机系统”区域中的P3端口用8芯排芯连接到“点阵模块”区域中的“DC1－DC8”端口上；
(3)．把“单片机系统”区域中的P2.0/A8端子用导线连接到“独立式键盘”区域中的SP1端子上；
4．程序设计内容
(1)．“★”在8X8LED点阵上显示图如下图所示

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12H，14H，3CH，48H，3CH，14H，12H，00H
(2)． “●”在8X8LED点阵上显示图如下图所示


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00H，00H，38H，44H，44H，44H，38H，00H
(3)．心形图在8X8LED点阵上显示图如下图所示


	●	●		●	●
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30H，48H，44H，22H，44H，48H，30H，00H
5．汇编源程序
CNTA       EQU 30H
COUNT EQU 31H
               ORG 00H
               LJMP START
               ORG 0BH
               LJMP T0X
               ORG 30H
START:    MOV CNTA,#00H
               MOV COUNT,#00H
               MOV TMOD,#01H
               MOV TH0,#(65536-4000) / 256
               MOV TL0,#(65536-4000) MOD 256
               SETB TR0
               SETB ET0
               SETB EA
WT:          JB P2.0,WT
               MOV R6,#5
               MOV R7,#248
D1:          DJNZ R7,$
               DJNZ R6,D1
               JB P2.0,WT
               INC COUNT
               MOV A,COUNT
               CJNE A,#03H,NEXT
               MOV COUNT,#00H
NEXT:    JNB P2.0,$
               SJMP WT
T0X: NOP
               MOV TH0,#(65536-4000) / 256
               MOV TL0,#(65536-4000) MOD 256
               MOV DPTR,#TAB
               MOV A,CNTA
               MOVC A,@A+DPTR
               MOV P3,A
               MOV DPTR,#GRAPH
               MOV A,COUNT
               MOV B,#8
               MUL AB
               ADD A,CNTA
               MOVC A,@A+DPTR
               MOV P1,A
               INC CNTA
               MOV A,CNTA
               CJNE A,#8,NEX
               MOV CNTA,#00H
NEX:       RETI
TAB:       DB 0FEH,0FDH,0FBH,0F7H,0EFH,0DFH,0BFH,07FH
GRAPH: DB 12H,14H,3CH,48H,3CH,14H,12H,00H
               DB 00H,00H,38H,44H,44H,44H,38H,00H
               DB 30H,48H,44H,22H,44H,48H,30H,00H
               END
6．C语言源程序
#include
unsigned char code tab[]={0xfe,0xfd,0xfb,0xf7,0xef,0xdf,0xbf,0x7f};
unsigned char code graph[3][8]={{0x12,0x14,0x3c,0x48,0x3c,0x14,0x12,0x00},
                              {0x00,0x00,0x38,0x44,0x44,0x44,0x38,0x00},
                              {0x30,0x48,0x44,0x22,0x44,0x48,0x30,0x00}
                           };
unsigned char count;
unsigned char cnta;
void main(void)
{
  unsigned char i,j;
  TMOD=0x01;
  TH0=(65536-4000)/256;
  TL0=(65536-4000)%6;
  TR0=1;
  ET0=1;
  EA=1;
  while(1)
{
   if(P2_0==0)
      {
      for(i=5;i>0;i--)
      for(j=248;j>0;j--);
      if(P2_0==0)
         {
            count++;
            if(count==3)
            {
               count=0;
            }
            while(P2_0==0);
         }
      }
}
}
void t0(void) interrupt 1 using 0
{
  TH0=(65536-4000)/256;
  TL0=(65536-4000)%6;
  P3=tab[cnta];
  P1=graph[count][cnta];
  cnta++;
  if(cnta==8)

作者: dalaochen 时间: 2009-12-12 18:58

了解一下。

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